Find the value of the expression (4x−12)+(12xy−10)(4x-12)+(12xy-10) for x=4 and y=6

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keithphakeokotou30h8 keithphakeokotou30h8

03-08-2017
Mathematics

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Find the value of the expression (4x−12)+(12xy−10)(4x-12)+(12xy-10) for x=4 and y=6

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evanrackel evanrackel · Answer 1 · 2017-08-03T02:09:53+02:00

(4x−12)+(12xy−10)(4x-12)+(12xy-10) = 4x-12 + 12.4.x.x.y - 12.12 .xy -10.4.x + 10.12 + 12xy - 10
= 4x - 10 +48(x^2)y - 144xy - 40x + 120 + 12xy -10
= 48yx^2 + 4x -40x -144xy + 12xy -10+120-10
= 48yx^2 - 36x - 132xy + 100
For x = 4 and y = 6
(4x−12)+(12xy−10)(4x-12)+(12xy-10) = 48yx^2 - 36x - 132xy + 100
= 48.6.(4^2) - 36.4 - 132.4.6 + 100
= 4608 - 144 - 3168 + 100
= 1396